I would like a confirmation that I'm looking at out of plane shear strength correctly.
Wall thickness = 8 in. (nominal)
Solid Grouted
F'm = 1,500 psi
b=12 in.
d=5.25 in.
Ae=91.2 in2 (from the equivalent solid thickness)
#6 bars at 8"
Temp. & Shrinkage horizontal steel
Mu/Vud >1, Cd=1.2, Vm(max)=63CdAe=63(1.2)(91.2)=6,895 lbs.
Vm=CdAe√F'm)=(1.2)(91.2)√(1,500)=4,239 lbs. < 6,895 lbs.
Vs = 0 since ρn = 0 (no shear reinforcement)
Vn = 4,239 lbs.
φv = 0.6
φv Vn = (0.6)(4,239) = 2,543 lbs.
Is this right?
If so, shear is limiting my design using strength design and it didn't come anywhere close using working stress design.
TIA,
T. William (Bill) Allen, S.E.
Consulting Structural Engineers
V (949) 248-8588 •